Changes

2nd: Array 1 will set the values in its first row [0,1] (marked by 2) index to the values in Array 2's 1st column and 1st [1,0] (marked by )index.

3rd: Finally Next Array 1 will calculate its 2nd next column (marked by the 3) by performing a calculation as shown above on 2 columns in Array 2 which will be represented by the Thread Identifier as the X dimension and the Y dimension being represented 's first column (marked by the for loop iterator3 ).

o3xxx 33xxx 3xxxx

o3xxx 33xxx  o3xxx 33xxx  o3xxx 33xxx  o3xxx 33xxx   __global__ void Calculate (float* u, float* un,int nx, int c, float dx, float dt) { int j = blockIdx.x * blockDim.x + threadIdx.x; int i = blockIdx.y * blockDim.y + threadIdx.y; // removes from instructions because no need to do this NX amount of times float total = c*dt / dx; if (i < nx && j < nx) { for (int it = 1; it <= nx- 1; it++) { if (i != 0 || i < nx ) { un[i * nx + it-1] = u[i * nx + it-1]; __syncthreads(); u[it] = un[1 * nx + it - 1]; __syncthreads(); u[i * nx + it ] = un[i * nx + it- 1] - c*dt / dx* (un[i * nx + it - 1] - un[(i - 1) * nx + it - 1]); __syncthreads(); } } }3xxxx

void init(float* u, int nx) { /*Initialize all values to 0, switching from vector to This process will loop until it has reached end of the array. Vector defaults to 0, array defaults to null*/ for (int i = 0; i < nx; i++) { for (int k = 0; k < nx; k++) u[i * nx + k] = 0; } }