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→ANSWER:
It will call up the function "d" in Makefile, and function "d" will call-up function "a", then function "a" will run print out the content of file "b" and "c" into a file called "a"
then, at the end of function "d", it will tar (with compress) file "a" to a tar file called "e"
'''Why? -- There is something that specifically triggers the target 'a' ... also, careful with terminology, use 'target' and 'dependency' '''
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Nes
