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J.Y.S

9 bytes added, 22:58, 19 October 2010
4.
''James''
<pre>
select substr(first_name ||' '|| last_name) "Employee", job_id, to_char(salary, '$999,999', 12, '=') Salary, department_name
from employees e join departments d
on (e.department_id = d.department_id)
1
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