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J.Y.S

271 bytes added, 22:35, 19 October 2010
3.
''James''
<pre>
select last_name, salary, job_id, nvl(to_char(manager_id),'No Manager') Manager#,
to_char(salary*12,'$999,999') "Total Income"
from employees
where (upper(job_id) like 'MK%' or manager_id IS NULL)
and salary * (1 + nvl(commission_pct, 0)) + 1000 > 10000
order by 2 desc;
</pre>
1
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