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J.Y.S
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,
00:04, 20 October 2010
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8.
''James''
<pre>
select department_id, department_name, substr(nvl(city,'Not Assigned Yet'),1,25) City, count(
DISTINCT
distinct
job_id)
'
"
# of Jobs
'
"
from employeesright outer join departments
using (department_id)
left outer join locations
James.Shaw
1
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