70
edits
Changes
→xor_me
001 ^ 010 ^ 111 = 110
110 ^ 111 ^ 111 = 110
</pre>
The first iteration of this loop executes a special condition which we must deal with before anything else:
<pre>
if (o == 32) {
r[0] = '\0';
hash = lclGetHash(t, r, 16);
}
</pre>
=== Assignment 3 ===