This page is to efficiently manage our group assignments!
Member List
First Name | Last Name | Student ID | Learn e-mail | Phone |
---|---|---|---|---|
YuJin | Jeong | 048 - 056 - 097 | yjeong | (647) 863 - 5555 |
Seung Yeon | Moon | - | symoon | (647) 678 - 6511 |
Li Shi | Zhou | 057 - 268 - 070 | lzhou | (416) 887 - 6758 |
Assignment 1 (worth 10%)
Due Date
Friday, October 21st, X:XXpm
Description
Solution - Example
1.
YuJin
SELECT department_id, department_name, RPAD(TRIM(NVL(city, 'Not Assinged Yet')), 25, ' ') "City", COUNT(DISTINCT job_id) "# of Jobs" FROM employees RIGHT OUTER JOIN departments USING (department_id) LEFT OUTER JOIN locations USING (location_id) GROUP BY department_id, department_name, city;
Seung Yeon
SELECT department_id, department_name, SUBSTR(NVL(city,'Not Assigned Yet'),1,25) City, COUNT(DISTINCT job_id) "# of Jobs" FROM locations l RIGHT OUTER JOIN departments d USING (location_id) LEFT OUTER JOIN employees e USING (department_id) GROUP BY department_id, department_name, city /
Li Shi
select department_id, department_name, substr(nvl(city,'Not Assigned Yet'),1,25) City, count(distinct job_id) "# of Jobs" from employees right outer join departments using (department_id) left outer join locations using (location_id) group by department_id, department_name, city
FINAL
SELECT department_id, department_name, SUBSTR(NVL(city, 'Not Assinged Yet'),1, 25) "City", COUNT(DISTINCT job_id) "# of Jobs" FROM employees RIGHT OUTER JOIN departments USING (department_id) LEFT OUTER JOIN locations USING (location_id) GROUP BY department_id, department_name, city;