Group 6
Group 6
Team Members
Progress
Assignment 1 - Select and Assess
Array Processing
Subject: Array Processing
Blaise Barney introduced Parallel Computing https://computing.llnl.gov/tutorials/parallel_comp/ Array processing could become one of the parallel example, which "demonstrates calculations on 2-dimensional array elements; a function is evaluated on each array element."
Here is my source code
arrayProcessing.cpp |
---|
// arrayProcessing.cpp // Array processing implement parallel solution #include <iostream> #include <iomanip> #include <cstdlib> #include <ctime> void init(float** randomValue, int n) { //std::srand(std::time(nullptr)); float f = 1.0f / RAND_MAX; for (int i = 0; i < n; i++) for (int j = 0; j < n; j++) randomValue[i][j] = std::rand() * f; } void multiply(float** a, float** b, float** c, int n) { for (int i = 0; i < n; i++) for (int j = 0; j < n; j++) { float sum = 0.0f; for (int k = 0; k < n; k++) sum += a[i][k] * b[k][j]; c[i][j] = sum; if(n <= 10){ std::cout << "array c[" << i << "," << j << "]: " << c[i][j] << std::endl; } } } int main(int argc, char* argv[]) { // interpret command-line argument if (argc != 2) { std::cerr << argv[0] << ": invalid number of arguments\n"; std::cerr << "Usage: " << argv[0] << " size_of_matrices\n"; return 1; } int n = std::atoi(argv[1]); // size of matrices float** a = new float*[n]; for (int i = 0; i < n; i++) a[i] = new float[n]; float** b = new float*[n]; for (int i = 0; i < n; i++) b[i] = new float[n]; float** c = new float*[n]; for (int i = 0; i < n; i++) c[i] = new float[n]; std::srand(std::time(nullptr)); init(a, n); init(b, n); multiply(a, b, c, n); for (int i = 0; i < n; i++) delete [] a[i]; delete [] a; for (int i = 0; i < n; i++) delete [] b[i]; delete [] b; for (int i = 0; i < n; i++) delete [] c[i]; delete [] c; } |
Standard random method is used to initialize a 2-dimentional array. The purpose of this program is to perform a 2-dimension array calculation, which is a matrix-matrix multiplication in this example.
In this following profile example, n = 1000
Flat profile: Each sample counts as 0.01 seconds. % cumulative self self total time seconds seconds calls Ts/call Ts/call name 100.11 1.48 1.48 multiply(float**, float**, float**, int) 0.68 1.49 0.01 init(float**, int) 0.00 1.49 0.00 1 0.00 0.00 _GLOBAL__sub_I__Z4initPPfi
Call graph granularity: each sample hit covers 2 byte(s) for 0.67% of 1.49 seconds index % time self children called name <spontaneous> [1] 99.3 1.48 0.00 multiply(float**, float**, float**, int) [1] ----------------------------------------------- <spontaneous> [2] 0.7 0.01 0.00 init(float**, int) [2] ----------------------------------------------- 0.00 0.00 1/1 __libc_csu_init [16] [10] 0.0 0.00 0.00 1 _GLOBAL__sub_I__Z4initPPfi [10] ----------------------------------------------- � Index by function name [10] _GLOBAL__sub_I__Z4initPPfi (arrayProcessing.cpp) [2] init(float**, int) [1] multiply(float**, float**, float**, int)
From the call graph, multiply() took major runtime to more than 99%, as it contains 3 for-loop, which T(n) is O(n^3). Besides, init() also became the second busy one, which has a O(n^2).
As the calculation of elements is independent of one another - leads to an embarrassingly parallel solution. Arrays elements are evenly distributed so that each process owns a portion of the array (subarray). It can be solved in less time with multiple compute resources than with a single compute resource.
The Monte Carlo Simulation (PI Calculation)
Subject: The Monte Carlo Simulation (PI Calculation) Got the code from here: https://rosettacode.org/wiki/Monte_Carlo_methods#C.2B.2B A Monte Carlo Simulation is a way of approximating the value of a function where calculating the actual value is difficult or impossible.
It uses random sampling to define constraints on the value and then makes a sort of "best guess."
Source Code |
---|
#include<iostream> #include<fstream> #include<math.h> #include<stdlib.h> #include<time.h> using namespace std; void calculatePI(int n, float* h_a) { float x, y; int hit; srand(time(NULL)); for (int j = 0; j < n; j++) { hit = 0; x = 0; y = 0; for (int i = 0; i < n; i++) { x = float(rand()) / float(RAND_MAX); y = float(rand()) / float(RAND_MAX); if (y <= sqrt(1 - (x * x))) { hit += 1; } } h_a[j] = 4 * float(hit) / float(n); } } int main(int argc, char* argv[]) { if (argc != 2) { std::cerr << argv[0] << ": invalid number of arguments\n"; std::cerr << "Usage: " << argv[0] << " size_of_matrices\n"; return 1; } int n = std::atoi(argv[1]); // scale float* cpu_a; cpu_a = new float[n]; calculatePI(n, cpu_a); ofstream h_file; h_file.open("h_result.txt"); float cpuSum = 0.0f; for (int i = 0; i < n; i++) { cpuSum += cpu_a[i]; h_file << "Host: " << cpu_a[i] << endl; } cpuSum = cpuSum / (float)n; cout << "CPU Result: " << cpuSum << endl; h_file.close(); } |
Zhijian
Subject:
Assignment 2 - Parallelize
Serial Code:
void calculatePI(int n, float* h_a) { float x, y; int hit; srand(time(NULL)); for (int j = 0; j < n; j++) { hit = 0; x = 0; y = 0; for (int i = 0; i < n; i++) { x = float(rand()) / float(RAND_MAX); y = float(rand()) / float(RAND_MAX); if (y <= sqrt(1 - (x * x))) { hit += 1; } } h_a[j] = 4 * float(hit) / float(n); } }
Parallel code:
__global__ void setRng(curandState *rng) { int idx = blockIdx.x * blockDim.x + threadIdx.x; curand_init(123456, idx, 0, &rng[idx]); } __global__ void calPI(float* d_a, int n, curandState *rng) { int idx = blockIdx.x * blockDim.x + threadIdx.x; unsigned int counter = 0; while (counter < n) { float x = curand_uniform(&rng[idx]); float y = curand_uniform(&rng[idx]); if (y <= sqrt(1 - (x * x))) { d_a[idx]++; } counter++; } d_a[idx] = 4.0 * (float(d_a[idx])) / float(n); }
Assignment 3 - Optimize
Here is my final source code
p03_reduction.cu |
---|
// part 3.1 : reduction // update 2: // add comments to all kernels // mdf kernel 2 only returns the numbers of dot inside the quadrant, and this number passes to next blocks // new kernel 3 sums the elements of d_a as generated by the kernel 2, and accumulate the block sums // new kernel 4 sums all block PI value before passing back to host #include<iostream> #include<fstream> #include<math.h> #include<stdlib.h> #include<time.h> #include <chrono> #include <cstdlib> #include <iomanip> #include <cuda_runtime.h> #include <curand_kernel.h> // to remove intellisense highlighting #include <device_launch_parameters.h> #ifndef __CUDACC__ #define __CUDACC__ #endif #include <device_functions.h> using namespace std; using namespace std::chrono; const int ntpb = 512; // this function uses to calculate PI on CPU void calculatePI(int n, float* h_a) { float x, y; int hit; srand(time(NULL)); for (int j = 0; j < n; j++) { hit = 0; x = 0; y = 0; for (int i = 0; i < n; i++) { x = float(rand()) / float(RAND_MAX); y = float(rand()) / float(RAND_MAX); if (y <= sqrt(1 - (x * x))) { hit += 1; } } h_a[j] = 4 * float(hit) / float(n); } } // kernel 1 // The first kernel uses to generate random numbers __global__ void setRng(curandState *rng) { int idx = blockIdx.x * blockDim.x + threadIdx.x; curand_init(123456, idx, 0, &rng[idx]); } // kernel 2 // The second kernel identifis the dot location (use the kernel 1 passed random number to create) // whether it is been in the quadrant or not __global__ void calPI(float* d_a, int n, curandState *rng) { int idx = blockIdx.x * blockDim.x + threadIdx.x; unsigned int counter = 0; // this variable counts the total number of dot be placed unsigned int hit = 0; // this variable counts the number of dot inside the cirle // in one Threat, it generates n dots while (counter < n) { float x = curand_uniform(&rng[idx]); float y = curand_uniform(&rng[idx]); if (y*y <= (1 - (x * x))) { hit++; } counter++; } d_a[idx] = 4.0 * (float(hit)) / float(n); } // kernel 3 // the third kernel sum the result in each block __global__ void sumPi(float* d_a, float*d_b, const int n) { int i = blockIdx.x * blockDim.x + threadIdx.x; int t = threadIdx.x; __shared__ float s[ntpb]; s[t] = d_a[i]; __syncthreads(); // sum the data in shared memory for (int stride = 1; stride < blockDim.x; stride <<= 1) { if ((t % (2 * stride) == 0) && (i + stride < n)) { s[t] += s[t + stride]; } __syncthreads(); } // store the sum in d_b; if (t == 0) { d_b[blockIdx.x] = s[0]; } } // kernel 4 // the forth kernel sum the result of all blocks __global__ void accumulate(float* c, const int nblocks) { // store the elements of c[] in shared memory int i = blockIdx.x * blockDim.x + threadIdx.x; int t = threadIdx.x; __shared__ float s[ntpb]; s[t] = c[i]; __syncthreads(); // sum the data in shared memory for (int stride = 1; stride < blockDim.x; stride <<= 1) { if ((t % (2 * stride) == 0) && (i + stride < nblocks)) { s[t] += s[t + stride]; } __syncthreads(); } // store the sum in c[0] if (t == 0) { c[blockIdx.x] = s[0]; } } void reportTime(const char* msg, steady_clock::duration span) { auto ms = duration_cast<milliseconds>(span); std::cout << msg << " took - " << ms.count() << " millisecs" << std::endl; } int main(int argc, char* argv[]) { if (argc != 2) { std::cerr << argv[0] << ": invalid number of arguments\n"; std::cerr << "Usage: " << argv[0] << " size_of_matrices\n"; return 1; } int n = std::atoi(argv[1]); // scale int nblks = (n + ntpb - 1) / ntpb; cout << "scale: " << n << endl << endl; steady_clock::time_point ts, te; float* cpu_a; cpu_a = new float[n]; ts = steady_clock::now(); calculatePI(n, cpu_a); te = steady_clock::now(); reportTime("CPU", te - ts); ofstream h_file; h_file.open("h_result.txt"); float cpuSum = 0.0f; for (int i = 0; i < n; i++) { cpuSum += cpu_a[i]; h_file << "Host: " << cpu_a[i] << endl; } cpuSum = cpuSum / (float)n; cout << "CPU Result: " << cpuSum << endl; h_file.close(); cout << endl; //////////////////////////////////////// curandState *d_rng; float* d_a; float* d_b; float* h_a; h_a = new float[n]; cudaMalloc((void**)&d_a, n * sizeof(float)); cudaMalloc((void**)&d_b, n * sizeof(float)); cudaMalloc((void**)&d_rng, n * sizeof(curandState)); ts = steady_clock::now(); setRng << < nblks, ntpb >> > (d_rng); cudaDeviceSynchronize(); // calculate PI in each thread and pass its value calPI << <nblks, ntpb >> > (d_a, n, d_rng); cudaDeviceSynchronize(); // sum PI in total and pass back on the device sumPi << <nblks, ntpb >> > (d_a, d_b, n); cudaDeviceSynchronize(); // accumulate the block sums accumulate << <1, nblks >> >(d_b, nblks); cudaDeviceSynchronize(); te = steady_clock::now(); reportTime("GPU", te - ts); // host h_a only receives one element from device d_b cudaMemcpy(h_a, d_b, n * sizeof(float), cudaMemcpyDeviceToHost); ofstream d_file; d_file.open("d_result.txt"); float gpuSum = 0.0f; gpuSum = h_a[0] / (float)n; cout << "GPU Result: " << gpuSum << "\n \n"<< endl; d_file.close(); cudaFree(d_a); cudaFree(d_rng); delete[] cpu_a; delete[] h_a; // reset the device cudaDeviceReset(); } |