Revision as of 07:16, 14 June 2017

OBJECTIVES

This lab will provide you will additional scripting tools to help us write even more effective Python scripts to be applied to practical application involving VM management and deployment in future labs.

The first investigation in this lab will focus on Data Structures. In Wikipedia (http://searchsqlserver.techtarget.com/definition/data-structure)
"A data structure is defined as a specialized format for organizing and storing data. Any data structure is designed to organize data to suit a specific purpose so that it can be accessed and worked with in appropriate ways."

Each data structure has its own advantages and limitations. This lab will emphasize the most important differences as they relate to Python scripting.

The second investigation will focus closely on strings. You have been using and storing strings since our first class, however in this lab we will dive into the more complex nature of string manipulation. Finally, this lab will cover how to use a variety of different regular expression functions, for searching and input validation.

PYTHON REFERENCE

For additional reference while working through this course.

Tuples

https://docs.python.org/3/tutorial/datastructures.html#tuples-and-sequences

Sets

https://docs.python.org/3/tutorial/datastructures.html#sets

Dictionaries

https://docs.python.org/3/tutorial/datastructures.html#dictionaries

Lists and List Comprehension

Strings

Regular Expressions:

INVESTIGATION 1: DATA STRUCTURES

PART 1 - Tuple

A Python Tuple is a number of immutable Python values. This is similar to a list in a lot of ways, except that, the value inside cannot be changed.

Perform the Following Steps:

Start by opening the ipython3 shell
```
ipython
```

Create two tuples to experiment with

t1 = ('Prime', 'Ix', 'Secundus', 'Caladan')
t2 = (1, 2, 3, 4, 5, 6)

Values from a tuple can be retreived in the same way as a list.
```
t1[0]
t2[2:4]
```
Or check if a value exists inside a tuple.
```
'Ix' in t1
'Geidi' in t1
```
Try changing a tuple value.
```
t2[1] = 10
```
Did it work? Once created the tuple values will not be able to change. If you would like a tuple with different values than the tuple you currently have, you must create a new one.
```
t3 = t2[2:3]
```

You however can still use most of the basic operations you might expect from tuples.

len(t1)     # list the length of the tuple
t1 * 3      # repitition
t1 + t2     # concatenation, remember this is creating a new tuple, not modifying

Like lists, you can also loop through the values of tuples.
```
for item in t1:
    print('item: ' + item)
```

PART 2 - Set

Sets are another very similar structure to lists, they can also be modified and changed, unlike the tuple. But sets have two unique characteristics, they are unordered, and they cannot have duplicate values. The unordered part provides a added performance from hashing the values, but also means we cannot pull out a specific value at a spefici position. Any duplicate entries will immediately be deleted. Sets however are great tools for doing comparisons, finding differences in multiple sets, or finding similarities. The best part about sets are, they are fast!

Perform the Following Steps:

Start the ipython3 shell:
```
ipython3
```

Create a couple sets to work with.

s1 = {'Prime', 'Ix', 'Secundus', 'Caladan'}
s2 = {1, 2, 3, 4, 5}
s3 = {4, 5, 6, 7, 8}

First, access a set through the index.
```
s1[0]
```
This should have created an error, this is not how to access data inside a set because they are unordered. Instead check to see if a value is inside.
```
'Ix' in s1
'Geidi' in s1
```
Sets can be combined together, any duplicates that the 2 sets share, will be deleted. Take a close look at which items are shared between the sets.
```
s2
s3
s2 | s3         # returns a set containing all values from both sets
s2.union(s3)    # same as s2 | s3
```

Instead of combining sets, we can find out what values are in both sets. This is a intersection between the lists.

s2
s3
s2 & s3             # returns a set containing all values that s2 and s3 share
s2.intersection(s3) # same as s2 & s3

Sets can have their values compared against other sets. First find out what items are in s2 but not in s3. This is also called a difference. But notice that it only shows values that s2 contains, specifically values that s3 doesn't have. So this isn't really the true difference between the sets.
```
s2
s3
s2 - s3             # returns a set containing all values in s2 that are not found s3
s2.difference(s3)   # same as s2 - s3
```
In order to see every difference between both sets, find the symmetric difference. This will return a set that shows all numbers that both sets do not share together.
```
s2
s3
s2 ^ s3                     # returns a set containing all values that both sets DO NOT share
s2.symmetric_difference(s3) # same as s2 ^ s3
```
These powerful features can be useful and efficient, try applying them to lists. Lists cannot perform these operations on them, instead we have to convert the lists into sets. Perform the comparision then convert the list back to a set. There are two problems with doing this: First, sets are unordered so if the list order is important this will cause problems and remove order, second, sets cannot contain duplicate values, if the list contains any duplicate values they will be deleted. However, if the list does not have any of the above requirements this is a great solution to some problems.
```
l2 = [1, 2, 3, 4, 5]
l3 = [4, 5, 6, 7, 8]
new_list = list(set(l2).intersection(set(l3)))  # set() can make lists into sets. list() can make sets into lists
new_list
```

Create a Python Script Demonstrating Comparing Sets

Perform the Following Instructions

Create the ~/ops435/lab4/lab4a.py script. The purpose of this script will be to demonstrate the different way of comparing sets. There will be three functions, each returning a different set comparison.

Use this template to get started:

#!/usr/bin/env python3

def join_sets(set1, set2):
    # join_sets will return a set that has every value from both set1 and set2 inside it

def match_sets(set1, set2):
    # match_sets will return a set that contains all values found in both set1 and set2

def diff_sets(set1, set2):
    # diff_sets will return a set that contains all different values which are not shared between the sets

if __name__ == '__main__':
    set1 = set(range(1,10))
    set2 = set(range(5,15))
    print('set1: ', set1)
    print('set2: ', set2)
    print('join: ', join_sets(set1, set2))
    print('match: ', match_sets(set1, set2))
    print('diff: ', diff_sets(set1, set2))

The match_sets() function should return a set that contains all values found in both sets
The diff_sets() function should return a set that contains all values which are not shared between both sets
The join_sets() function should return a set that contains all values from both sets
All three functions should accept two arguments both are sets
The script should show the exact output as the samples
The script should contain no errors

Sample Run 1:

run lab4a.py
set1:  {1, 2, 3, 4, 5, 6, 7, 8, 9}
set2:  {5, 6, 7, 8, 9, 10, 11, 12, 13, 14}
join:  {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}
match:  {8, 9, 5, 6, 7}
diff:  {1, 2, 3, 4, 10, 11, 12, 13, 14}

Sample Run 2(with import):

import lab4a
set1 = {1,2,3,4,5}
set2 = {2,1,0,-1,-2}
lab4a.join_sets(set1,set2)
{-2, -1, 0, 1, 2, 3, 4, 5}
lab4a.match_sets(set1,set2)
{1, 2}
lab4a.diff_sets(set1,set2)
{-2, -1, 0, 3, 4, 5}

3. Exit the ipython3 shell, download the checking script and check your work. Enter the following commands from the bash shell.

cd ~/ops435/lab4/
pwd #confirm that you are in the right directory
ls CheckLab4.py || wget matrix.senecac.on.ca/~acoatley-willis/CheckLab4.py
python3 ./CheckLab4.py -f -v lab4a

4. Before proceeding, make certain that you identify any and all errors in lab4a.py. When the checking script tells you everything is OK before proceeding to the next step.

Create a Python Script Demonstrating Comparing Lists

Perform the Following Instructions

Create the ~/ops435/lab4/lab4b.py script. The purpose of this script will be to improve the previous script to perform the same joins, matches, and diffs, but this time on lists.

Use the following as a template:

#!/usr/bin/env python3

def join_lists(list1, list2):
    # join_lists will return a list that contains every value from both list1 and list2 inside it

def match_lists(list1, list2):
    # match_lists will return a list that contains all values found in both list1 and list2

def diff_lists(list1, list2):
    # diff_lists will return a list that contains all different values, which are not shared between the lists

if __name__ == '__main__':
    list1 = list(range(1,10))
    list2 = list(range(5,15))
    print('list1: ', list1)
    print('list2: ', list2)
    print('join: ', join_lists(list1, list2))
    print('match: ', match_lists(list1, list2))
    print('diff: ', diff_lists(list1, list2))

The match_lists() function should return a list that contains all values found in both lists
The diff_lists() function should return a list that contains all values which are not shared between both lists
The join_lists() function should return a list that contains all values from both sets
All three functions should accept two arguments both are lists
The script should show the exact output as the samples
The script should contain no errors

Sample Run 1:

run lab4b.py
list1:  [1, 2, 3, 4, 5, 6, 7, 8, 9]
list2:  [5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
join:  [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
match:  [8, 9, 5, 6, 7]
diff:  [1, 2, 3, 4, 10, 11, 12, 13, 14]

Sample Run 2(with import):

import lab4b
list1 = [1,2,3,4,5]
list2 = [2,1,0,-1,-2]
join_lists(list1,list2)
[0, 1, 2, 3, 4, 5, -2, -1]
match_lists(list1,list2)                                                                                                                  
[8, 9, 5, 6, 7]
diff_lists(list1,list2)                                                                                                                   
[1, 2, 3, 4, 10, 11, 12, 13, 14]

3. Exit the ipython3 shell, download the checking script and check your work. Enter the following commands from the bash shell.

cd ~/ops435/lab4/
pwd #confirm that you are in the right directory
ls CheckLab4.py || wget matrix.senecac.on.ca/~acoatley-willis/CheckLab4.py
python3 ./CheckLab4.py -f -v lab4b

4. Before proceeding, make certain that you identify any and all errors in lab4b.py. When the checking script tells you everything is OK before proceeding to the next step.

PART 3 - Dictionary

In Python a Dictionary is a set of key-value pairs. Dictionaries are unordered, like sets, however any value can be retrieved from a dictionary if you know the key. This section will go over how to create, access, and change dictionaries, providing a new tool to store and manipulate data with.

Perform the Following Steps:

Start the ipython3 shell:
```
ipython3
```

Start by creating a new dictionary to practice with:

dict_york = {'Address': '70 The Pond Rd', 'City': 'Toronto', 'Postal Code': 'M3J3M6'}

The syntax here is to use {} to create a dictionary and placing key:value pairs inside separated by commas.
Take a close look at all the available functions available to dictionary objects
```
dir(dict_york)
help(dict_york)
```
All values can be viewed by using the dictionary.values() function. This function provides a list containing all values
```
help(dict_york.values)
dict_york.values()
```
All keys can be viewed by using the dictionary.keys() function. This function provides a list containing all keys
```
help(dict_york.keys)
dict_york.keys()
```
We can retrieve individual values from a dictionary by provide the key associated with the value
```
dict_york['Address']
dict_york['Postal Code']
```
Dictionary keys can be any immutable values, such as: strings, numbers, and tuples. Trying adding a couple new keys and values to the dictionary
```
dict_york['Country'] = 'Canada'
dict_york
dict_york.values()
dict_york.keys()
```

Study the output and add another key:value pair

dict_york['Province'] = 'BC'
dict_york
dict_york.values()
dict_york.keys()

Dictionary keys must be unique. Attempting to add a key that already exists in the dictionary will overwrite the existing value for that key
```
dict_york['Province'] = 'ON'
dict_york
dict_york.values()
dict_york.keys()
```
These lists that contain the values and keys of the dictionary are not real python lists, they are view of the dictionary
However we can change these from views into usable lists by using the list() function, the index can be used to access individual values
```
list_of_keys = list(dict_york.keys())
list_of_keys[0]
```

Lists can be changed into sets if we would like to perform comparisons with another set

set_of_keys = set(dict_york.keys())
set_of_values = set(dict_york.values())
set_of_keys | set_of_values

The lists can be iterated over in a for loop

list_of_keys = list(dict_york.keys())
for key in list_of_keys:
    print(key)
for value in dict_york.values()
    print(value)

The values and keys can be looped over using the index as well
The range() function provides a list of numbers in a range.

The len() provides a the number of items in a list. Used together len() and range() create a list of usable indexes for a specific list

list_of_keys = list(dict_york.keys())
list_of_values = list(dict_york.values())
list_of_indexes = range(0, len(dict_york.keys()))
list_of_indexes
list_of_keys[0]
list_of_values[0]

Using this this list of indexes we are able to pair the keys and values of two separate lists

list_of_keys = list(dict_york.keys())
list_of_values = list(dict_york.values())
for index in range(0, len(list_of_keys)):
    print(list_of_keys[index] + '--->' + list_of_values[index])

Looping using indexes is not the best way to loop through a dictionary. A new dictionary could be created using this method, but this is not good

list_of_keys = list(dict_york.keys())
list_of_values = list(dict_york.values())
new_dictionary = {}
for index in range(0, len(list_of_keys)):
    new_dictionary[list_of_keys[index]] = list_of_values[index]

The above method uses a lot of memory and loops. The best method to create a dictionary from two lists is to use the zip() function

list_of_keys = list(dict_york.keys())
list_of_values = list(dict_york.values())
new_dictionary = dict(zip(list_of_keys, list_of_values))

Loop through the keys in a dictionary also provides a easy way to get the value for each key at the same time
```
for key in dict_york.keys():
    print(key + '--->' + dict_york[key])
```
Even better than the above, both key and value can be extracted in a single for loop using a special object
```
for key, value in dict_york.items():
    print(key + ' | ' + value)
```

Create a Python Script for Managing Dictionaries

Perform the Following Instructions

Create the ~/ops435/lab4/lab4c.py script. The purpose of this script will be to create dictionaries, extract data from dictionaries, and to make comparisons between dictionaries.

Use the following as a template:

#!/usr/bin/env python3

# Dictionaries
dict_york = {'Address': '70 The Pond Rd', 'City': 'Toronto', 'Country': 'Canada', 'Postal Code': 'M3J3M6', 'Province': 'ON'}
dict_newnham = {'Address': '1750 Finch Ave E', 'City': 'Toronto', 'Country': 'Canada', 'Postal Code': 'M2J2X5', 'Province': 'ON'}
# Lists
list_keys = ['Address', 'City', 'Country', 'Postal Code', 'Province']
list_values = ['70 The Pond Rd', 'Toronto', 'Canada', 'M3J3M6', 'ON']

def create_dictionary(keys, values):
    # Place code here

def split_dictionary(dictionary):
    # Place code here
       
def shared_values(dict1, dict2):
    # Place code here

if __name__ == '__main__':
    york = create_dictionary(list_keys, list_values)
    print('York: ', york)
    keys, values = split_dictionary(dict_newnham)
    print('Newnham Keys: ', keys)
    print('Newnham Values: ', values)
    keys, values = split_dictionary(york)
    print('York Keys: ', keys)
    print('York Values: ', values)
    common = shared_values(dict_york, dict_newnham)
    print('Shared Values', common)

The script should contain three functions
create_dictionary() accepts two lists as arguments keys and values, combines these lists together to create a dictionary
create_dictionary() returns a dictionary that has the keys and associated values from the lists
split_dictionary() accepts a single dictionary as a argument and splits the dictionary into two lists, keys and values
split_dictionary() returns two lists: return keys, values
shared_values() accepts two dictionaries as arguments finds all values that are shared between the two dictionaries
shared_values() returns a set containing ONLY values found in BOTH dictionaries
make sure the functions have the correct number of arguments required
The script should show the exact output as the samples
The script should contain no errors

Sample Run 1:

run lab4c.py
York:  {'Country': 'Canada', 'Postal Code': 'M3J3M6', 'Address': '70 The Pond Rd', 'Province': 'ON', 'City': 'Toronto'}
Newnham Keys:  ['Country', 'Postal Code', 'Address', 'Province', 'City']
Newnham Values:  ['Canada', 'M2J2X5', '1750 Finch Ave E', 'ON', 'Toronto']
York Keys:  ['Country', 'Postal Code', 'Address', 'Province', 'City']
York Values:  ['Canada', 'M3J3M6', '70 The Pond Rd', 'ON', 'Toronto']
Shared Values {'Canada', 'ON', 'Toronto'}

Sample Run 2(with import):

import lab4c
dict_york = {'Address': '70 The Pond Rd', 'City': 'Toronto', 'Country': 'Canada', 'Postal Code': 'M3J3M6', 'Province': 'ON'}
dict_newnham = {'Address': '1750 Finch Ave E', 'City': 'Toronto', 'Country': 'Canada', 'Postal Code': 'M2J2X5', 'Province': 'ON'}
list_keys = ['Address', 'City', 'Country', 'Postal Code', 'Province']
list_values = ['70 The Pond Rd', 'Toronto', 'Canada', 'M3J3M6', 'ON']

york = create_dictionary(list_keys, list_values)

york
{'Address': '70 The Pond Rd',
 'City': 'Toronto',
 'Country': 'Canada',
 'Postal Code': 'M3J3M6',
 'Province': 'ON'}

keys, values = split_dictionary(dict_newnham)

keys
['Country', 'Postal Code', 'Address', 'Province', 'City']

values
['Canada', 'M2J2X5', '1750 Finch Ave E', 'ON', 'Toronto']

keys, values = split_dictionary(york)

keys
['Country', 'Postal Code', 'Address', 'Province', 'City']

values
['Canada', 'M3J3M6', '70 The Pond Rd', 'ON', 'Toronto']

common = shared_values(dict_york, dict_newnham)

common
{'Canada', 'ON', 'Toronto'}

3. Exit the ipython3 shell, download the checking script and check your work. Enter the following commands from the bash shell.

cd ~/ops435/lab4/
pwd #confirm that you are in the right directory
ls CheckLab4.py || wget matrix.senecac.on.ca/~acoatley-willis/CheckLab4.py
python3 ./CheckLab4.py -f -v lab4c

4. Before proceeding, make certain that you identify any and all errors in lab4c.py. When the checking script tells you everything is OK before proceeding to the next step.

PART 4 - List Comprehension

We've already covered lists to a degree. Lets move into more advanced functions to use and generate lists. This is a very common practice in Python, understanding how to generate, manipulate, and apply functions to items inside a list can be incredibly useful. List comprehension is a way to build new lists from existing list and to do it faster than simply looping over lists.

Perform the Following Steps

Lets start with creating a list and applying some function to each item in the list. The below will print out the square of each item.
```
l1 = [1, 2, 3, 4, 5]
for item in l1:
    print(item ** 2)
```
To store these squares for later use, create a new list and append the squares to it. This will generate a new list that contains squared values in the same positions of the first list. This is using an existing list to create a new list.
```
l1 = [1, 2, 3, 4, 5]
l2 = []
for item in l1:
    l2.append(item ** 2)
l1
l2
```
Move the squaring of numbers out into it's own separate function. While the squaring example is a simple function, this example could include a more complex function that does more processing on each item in the list.
```
def square(number):
    return number ** 2

l1 = [1, 2, 3, 4, 5]
l2 = []
for item in l1:
    l2.append(square(item))

l1
l2
```
The map function can be used to apply a function on each item in a list. This is exactly what happened above, however it gives much better syntax, removes the loop, including the variable that was created inside the loop. This will make the script a little more efficient while performing the same task.
```
def square(number):
    return number ** 2

l1 = [1,2,3,4,5]
l2 = list(map(square, l1))

l1
l2
```
The above map function requires a function, and a list. This meant that before map() could be used a function needed to be defined earlier in the script. This entire process can be avoided through the use of anonymous functions. This is the ability to create a simple function without defining it, and pass it off for use. Below we will use lambda, which will return a function, and we can use that function immediately. The function takes 1 argument x, and it will perform a single operation on x, square it.
```
square = lambda x: x ** 2
l1 = [1,2,3,4,5]
l2 = list(map(square, l1))

l1
l2
```
The above code is actually not particularly good, the whole purpose of using lambda here is we were avoiding the function definition and just quickly returning a function. However this does break down exactly what lambda does, it returns a function for use. Fix this by removing the square function and just use the return function from lambda. Now remember what map requires? map's first argument is a function, and map's second argument is a list. Here lambda will return a function and provide it as the first argument.
```
l1 = [1,2,3,4,5]
l2 = list(map(lambda x: x ** 2, l1))

l1
l2
```
Using the list comprehensions above our code will be faster and more efficient than using multiple variables and loops.

INVESTIGATION 2: STRINGS

Strings are in their most basic form a list of characters, or a bit of text. Strings store text so that we can use them later. In this section we will cover more than just displaying that text to the screen. Here, we will go over cutting strings into sub-strings, joining strings together, searching through strings, and matching strings against patterns.

PART 1 - String Basics

PART 1 - String Manipulation

PART 1 - Regular Expressions

LAB 4 SIGN-OFF (SHOW INSTRUCTOR)

Students should be prepared with all required commands (system information) displayed in a terminal (or multiple terminals) prior to calling the instructor for signoff.

Have Ready to Show Your Instructor:

✓ x

✓ Lab4 logbook notes completed

Practice For Quizzes, Tests, Midterm & Final Exam

x
x
x

@@ Line 9: / Line 9: @@
 :The '''second investigation''' will focus closely on strings. You have been using and storing strings since our first class, however in this lab we will dive into the more complex nature of string manipulation. Finally, this lab will cover how to use a variety of different regular expression functions, for searching and input validation.
 <br><br>
-== PYTHON REFERENCE ==
+=== PYTHON REFERENCE ===
 For additional reference while working through this course.

Difference between revisions of "OPS435 Python Lab 4"

Revision as of 07:16, 14 June 2017

Contents

OBJECTIVES

PYTHON REFERENCE

INVESTIGATION 1: DATA STRUCTURES

PART 1 - Tuple

PART 2 - Set

PART 3 - Dictionary

PART 4 - List Comprehension

INVESTIGATION 2: STRINGS

PART 1 - String Basics

PART 1 - String Manipulation

PART 1 - Regular Expressions

LAB 4 SIGN-OFF (SHOW INSTRUCTOR)

Practice For Quizzes, Tests, Midterm & Final Exam

Navigation menu

Personal tools

Namespaces

Variants

Views

More

Search

Navigation

get involved with CDOT

courses

course projects

links

Tools